Find the current in the $10\,\Omega$ resistance. The circuit consists of two $5\,V$ batteries with internal resistances of $2\,\Omega$ each,connected in parallel with a $10\,\Omega$ resistor.

In the given circuit,the electric currents through $15 \Omega$ and $6 \Omega$ resistors respectively are:

Two resistances $R_1 = X \Omega$ and $R_2 = 1 \Omega$ are connected to a wire $AB$ of uniform resistivity,as shown in the figure. The radius of the wire varies linearly along its axis from $0.2 \text{ mm}$ at $A$ to $1 \text{ mm}$ at $B$. $A$ galvanometer $(G)$ connected to the center of the wire,$50 \text{ cm}$ from each end along its axis,shows zero deflection when $A$ and $B$ are connected to a battery. The value of $X$ is:

Seven resistances are connected as shown in the figure. The equivalent resistance between $A$ and $B$ is ............... $\Omega$.

Five conductors meet at a point $x$ as shown in the figure. What is the current flowing through the fifth conductor?

Five resistors,each of resistance $R$,are arranged as shown in the figure. $A$ battery of voltage $V$ is connected between points $A$ and $B$. Find the current flowing through the branch $AFCEB$.